Tuesday 30 August 2016

`(12, 8), (-4, -3)` Find the inclination 'theta' (in radians and degrees) of the line with slope m.

Given (12, 8) (-4, -3)



Find the slope of the line passing through the given points using the formula


`m=(y_2-y_1)/(x_2-x_1)`


` ` `m=(-3-8)/(-4-12)=[-11]/-16=11/16`



Find the angle of inclination.


`theta=arctan(11/16)=34.5^@=.6023`  radians.



The angle of inclination of the line passing through the given points is


34.5 degrees or .6023 radians. 



Given (12, 8) (-4, -3)



Find the slope of the line passing through the given points using the formula


`m=(y_2-y_1)/(x_2-x_1)`


` ` `m=(-3-8)/(-4-12)=[-11]/-16=11/16`



Find the angle of inclination.


`theta=arctan(11/16)=34.5^@=.6023`  radians.



The angle of inclination of the line passing through the given points is


34.5 degrees or .6023 radians. 



No comments:

Post a Comment

How can a 0.5 molal solution be less concentrated than a 0.5 molar solution?

The answer lies in the units being used. "Molar" refers to molarity, a unit of measurement that describes how many moles of a solu...