Help Notes: `(12, 8), (-4, -3)` Find the inclination 'theta' (in radians and degrees) of the line with slope m.

Tuesday, 30 August 2016

Given (12, 8) (-4, -3)

Find the slope of the line passing through the given points using the formula

$\displaystyle{m}=\frac{{{y}_{{2}}-{y}_{{1}}}}{{{x}_{{2}}-{x}_{{1}}}}$

$\displaystyle{m}=\frac{{-{3}-{8}}}{{-{4}-{12}}}=\frac{{-{11}}}{{-{{16}}}}=\frac{{11}}{{16}}$

Find the angle of inclination.

$\displaystyle\theta={\arctan{{\left(\frac{{11}}{{16}}\right)}}}={{34.5}}^{\circ}={.6023}$ radians.

The angle of inclination of the line passing through the given points is

34.5 degrees or .6023 radians.

Given (12, 8) (-4, -3)

Find the slope of the line passing through the given points using the formula

$\displaystyle{m}=\frac{{{y}_{{2}}-{y}_{{1}}}}{{{x}_{{2}}-{x}_{{1}}}}$

$\displaystyle{m}=\frac{{-{3}-{8}}}{{-{4}-{12}}}=\frac{{-{11}}}{{-{{16}}}}=\frac{{11}}{{16}}$

Find the angle of inclination.

$\displaystyle\theta={\arctan{{\left(\frac{{11}}{{16}}\right)}}}={{34.5}}^{\circ}={.6023}$ radians.

The angle of inclination of the line passing through the given points is

34.5 degrees or .6023 radians.

Help Notes