Wednesday 11 November 2015

`m = 1/2` find the inclination 'theta' (in radians and degrees) of the line with slope m.

The given slope is `m=1/2` .


Take note that if the slope of the line is given, to get the angle of inclination, apply the formula:


`tan theta =m`


Plugging in the given value of m, the formula becomes:


`tan theta = 1/2`


To isolate theta, take the inverse of tangent.


`theta = tan ^(-1) (1/2)`


`theta =0.4636476090 rad=26.56505117^o`


Rounding off to four decimal places, the values become:


`theta = 0.4636 rad = 26.5651^o`


Therefore,...

The given slope is `m=1/2` .


Take note that if the slope of the line is given, to get the angle of inclination, apply the formula:


`tan theta =m`


Plugging in the given value of m, the formula becomes:


`tan theta = 1/2`


To isolate theta, take the inverse of tangent.


`theta = tan ^(-1) (1/2)`


`theta =0.4636476090 rad=26.56505117^o`


Rounding off to four decimal places, the values become:


`theta = 0.4636 rad = 26.5651^o`


Therefore, the angle of inclination in radian is 0.4636 rad. And in degree, the angle of inclination is `26.5651^o .`

No comments:

Post a Comment

How can a 0.5 molal solution be less concentrated than a 0.5 molar solution?

The answer lies in the units being used. "Molar" refers to molarity, a unit of measurement that describes how many moles of a solu...